HYPOTHESIS TESTING
HELLO👋 and welcome back to another blog. This week we would be looking into hypothesis testing using our full and fractional factorial we have found during our practical. There are 3 factors we would be looking at. they are the stop/start angle and the length of the arm.
DOE practical team members:
1. Kalyani(me)
2. Jolyn
3. Brayden
4. Gideon
DATA COLLECTED FOR FULL FACTORIAL USING CATAPULT A:
DATA COLLECTED FOR FRACTIONAL FACTORIAL USING CATAPULT B:
KALYANI(ME) will use Run #4 from FRACTIONAL factorial and Run#4 from FULL factorial.
JOLYN will use Run #3 from FRACTIONAL factorial and Run#3
from FULL factorial.
BRAYDEN will use Run #5 from FRACTIONAL factorial and
Run#5 from FULL factorial.
GIDEON will use Run #6 from FRACTIONAL factorial and
Run#6 from FULL factorial.
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The QUESTION |
The catapult (the ones that were used in the DOE practical)
manufacturer needs to determine the consistency of the products they have manufactured.
Therefore they want to determine whether CATAPULT A produces the same flying
distance of projectile as that of CATAPULT B. |
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Scope of the
test |
The human factor is
assumed to be negligible. Therefore different user will not have any effect
on the flying distance of projectile.
Flying distance for
catapult A and catapult B is collected using the factors below: Arm length = 30.5cm Start angle = 20 degree Stop angle = 60 degree |
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Step 1: State the
statistical Hypotheses: |
State the null hypothesis
(H0): This means that there will not be any effect on the flying projectile. μA = μB
State the alternative
hypothesis (H1): This means it will have an effect on the flying projectile. |
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Step 2: Formulate an
analysis plan. |
Sample size is 8 which is lesser than 30. Therefore t-test will be used.
Since the sign of H1 is ≠, a two tailed test is used.
Significance level (α) used in this test is 0.05.
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Step 3: Calculate the
test statistic |
State the mean and
standard deviation of sample catapult A: mean: 98.8 standard deviation:14.38 State the mean and
standard deviation of sample catapult B: mean:127.9 standard deviation: 3.83 Compute the value of the
test statistic (t): T0.975
, V= 14, boundary t =2.145 |
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Step 4: Make a
decision based on result |
Type of test (check one
only)
T0.975 , V= 14 Critical value tα/2 = ± 2.145
since t=-5.17,Therefore Ho is rejected. |
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Conclusion
that answer the initial question |
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Compare your
conclusion with the conclusion from the other team members. What
inferences can you make from these comparisons? |
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